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Find the L.C.M. of 45,\tfrac{4}{5},54​,​ 38\tfrac{3}{8}83​​ and 98\tfrac{9}{8}89​​.
Question

Find the L.C.M. of 45,\tfrac{4}{5},​ 38\tfrac{3}{8}​ and 98\tfrac{9}{8}​.

A.

36

B.

9

C.

8

D.

28

Correct option is A

Given:

L.C.M. of 45,\tfrac{4}{5},​ 38\tfrac{3}{8}​ and98\tfrac{9}{8}

Concept Used: 

LCM of any fraction = LCM of numeratorHCF of denominator\frac{ LCM \ of \ numerator } { HCF \ of \ denominator}   

Solution: 

L.C.M. of 45,\tfrac{4}{5},​​​ 38\tfrac{3}{8}​​​ and98\tfrac{9}{8}​​.   

LCM = LCM of 4,3,9HCF of 5,8,8=361\frac{ LCM \ of \ 4 , 3, 9}{HCF \ of \ 5 , 8 , 8 } = \frac{36}{1}  = 36 ​

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