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    Find the L.C.M. of 45,\tfrac{4}{5},54​,​ 38\tfrac{3}{8}83​​ and 98\tfrac{9}{8}89​​.
    Question

    Find the L.C.M. of 45,\tfrac{4}{5},​ 38\tfrac{3}{8}​ and 98\tfrac{9}{8}​.

    A.

    36

    B.

    9

    C.

    8

    D.

    28

    Correct option is A

    Given:

    L.C.M. of 45,\tfrac{4}{5},​ 38\tfrac{3}{8}​ and98\tfrac{9}{8}

    Concept Used: 

    LCM of any fraction = LCM of numeratorHCF of denominator\frac{ LCM \ of \ numerator } { HCF \ of \ denominator}   

    Solution: 

    L.C.M. of 45,\tfrac{4}{5},​​​ 38\tfrac{3}{8}​​​ and98\tfrac{9}{8}​​.   

    LCM = LCM of 4,3,9HCF of 5,8,8=361\frac{ LCM \ of \ 4 , 3, 9}{HCF \ of \ 5 , 8 , 8 } = \frac{36}{1}  = 36 ​

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