Find the area (in square units) of a triangle with vertices (3,4),(5,7) and (-3,6).

Correct option is A

Given:

Vertices of a triangle = (3,4),(5,7) and (-3,6)

Formula Used:

Area of a triangle with vertices$$(x_1,y_1),(x_2,y_2) and (x_3,y_3)$$​​

Area = $$\frac{1}{2} [ x_1(y_2-y_3) + x_2(y_3-y_1)+x_3(y_1-y_2)]$$​​

Solution:

Here vertices are (3,4),(5,7) and (-3,6)

Area =$$\frac{1}{2}[ 3(7-6) + 5(6-4) -3(4-7)]$$​​

​$$= \frac{1}{2}[ 3+10+9]$$​​

​$$=\frac{1}{2}[22]$$​​

​$$= 11cm^2$$​​