Find the area (in $$cm^2$$) of the sector of a circle of radius 21 cm with a central angle of 60°. [Use π = 22/7]

Correct option is C

Given:
Radius of the circle, $$r = 21 \, \text{cm}$$​​
Central angle of the sector, $$\theta = 60^\circ$$​​

​$$\pi = \frac{22}{7}$$​​​​

Formula Used:

Area of sector = $$\frac{\theta}{360^\circ} \times \pi r^2$$​

Solution:
Area of sector = $$\frac{60^\circ}{360^\circ} \times \frac{22}{7} \times 21^2$$​

Area of sector = $$\frac{60}{360} \times \frac{22}{7} \times 441$$​

= $$\frac{1}{6} \times \frac{22}{7} \times 441$$​

= $$\frac{22 \times 441}{6 \times 7}$$​

= $$\frac{9702}{42}= 231$$​

The area of the sector is $${231} \, \text{cm}^2.$$​​
Thus, the correct option is (c) 231 cm²​