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Evaluate: 45 of 35÷127+3 of 13−1045\ \text{of } \frac{3}{5}÷1 \frac{2}{7}+3 \text{ of } \frac{1}{3}-1045 of 53​÷172
Question

Evaluate: 45 of 35÷127+3 of 13−1045\ \text{of } \frac{3}{5}÷1 \frac{2}{7}+3 \text{ of } \frac{1}{3}-10​​

A.

10

B.

14

C.

15

D.

12

Correct option is D

Given:
Expression: 45×35÷127+3×13−1045 \times \frac{3}{5} \div 1 \frac{2}{7} + 3 \times \frac{1}{3} - 10 
Concept Used: 
BODMAS rule: 
​Operation preference wiseSymbolBrackets[],,()Orders,of²(power),√(root),ofDivision÷Multiplication×Addition+Subtraction−\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}      
Solution:  
​45×35÷127+3×13−10 =45×35×79+3×13−10 =45×2145+1−10 =22−10=1245 \times \frac{3}{5} \div 1 \frac{2}{7} + 3 \times \frac{1}{3} - 10 \\ \ \\ = 45 \times \frac{3}{5} \times \frac{7}{9} + \cancel3 \times \frac{1}{\cancel3} - 10 \\ \ \\ = \cancel{45 }\times \frac{21}{\cancel {45}}+1 - 10 \\ \ \\ = 22 - 10 \\ = \bf12 ​​

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