Evaluate:

​$$\left(3\frac{1}{7} + 4\frac{3}{7}\right) + \frac{7}{6}$$​​

Correct option is A

Given:

$$\left(3\frac{1}{7} + 4\frac{3}{7}\right) + \frac{7}{6}$$

Concept Used: 

BODMAS rule:

​$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$​​

Solution:

$$\left(3\frac{1}{7} + 4\frac{3}{7}\right) + \frac{7}{6}$$

= $$\left(\frac{22}{7} +\frac{31}{7}\right)$$ $$+ \frac{7}{6}$$

= $$\frac{53}{7}$$ $$+ \frac{7}{6}$$​

= $$\frac{318+49}{42}$$​

=$$\frac{367}{42}$$