Correct option is BGiven:1(56)+(24)÷429\frac{1}{(\frac{5}{6}) + (\frac{2}{4}) } \div \frac{4}{29}(65)+(42)1÷294 Solution: =1(56)+(24)÷429 =110+612÷429 =1216×294 =8716 =5716= \frac{1}{(\frac{5}{6}) + (\frac{2}{4}) } \div \frac{4}{29} \\\ \\= \frac{1}{\frac{10+6}{12}} \div \frac{4}{29}\\\ \\= \frac{12}{16}\times \frac{29}{4} \\\ \\= \frac{87}{16} \\\ \\=5 \frac{7}{16}=(65)+(42)1÷294 =1210+61÷294 =1612×429 =1687 =5167