During a division, Pranjal mistakenly took as the dividend a number that was 10% more than the original dividend. He also mistakenly took as the divisor a number that was 25% more than the original divisor. If the correct quotient of the original division problem was 25 and the remainder was 0 , what was the quotient that Pranjal obtained, assuming his calculations had no error?

Pranjal mistakenly took:

A dividend that was 10% more than the original dividend.

A divisor that was 25% more than the original divisor.

The correct quotient of the original division is 25, and the remainder is 0.

Let the original dividend = 100x
Mistakenly increased dividend = 100 × 110% = 110x
Let original divisor = 100y
Mistakenly increased divisor = 100y × 125% = 125y
Dividend = divisor × quotient + remainder
100x = 100y × 25 + 0
x/y = 25/1
Increased dividend = 110x = 110 × 25 = 2750
Increased divisor = 125y = 125 × 1 = 125
Quotient = 2750/125 = 22 ​

Thus, correct option is (d).