Correct option is B
Concept used:
When smallest number asked, which when divided by a, b, c leaves the same remainder R in each case, that number is LCM[a, b, c] + R
Solution:
∴ Smallest number which when divided by 12,16, 20.25 and 30 leaves the same remainder 3 in each case is LCM[12,16, 20.25, 30] + 3
= 1200 + 3
= 1203