The largest four-digit number which when divided by 9, 18 and 23, leaves a remainder 5 in each case, is:
Given:
The required number leaves remainder 5 when divided by 9, 18 and 23.
Formula Used:
Required number = (LCM of divisors × k) + remainder
Solution:
LCM of 9, 18 and 23 = 414
Largest four-digit number ≈ 9999
9999 − 5 = 9994
9994 ÷ 414 = 24
Required number = (414 × 24) + 5 = 9941
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