Container A has 240 L of milk and water in the ratio of 8: 7. 30 L of mixture is taken out and replaced with same quantity of water and again 60 L of mixture is taken out and replaced with same quantity of water. Now container A and B which has 260 L of milk and water in the ratio of 8: 5 are mixed. Find the quantity of milk in the resultant mixture (in liters).

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Information Given in the Question:

Container A: 240 L of milk and water in the ratio 8:7

Step 1: 30 L mixture removed, replaced with 30 L water

Step 2: 60 L mixture removed, replaced with 60 L water

Container B: 260 L of milk and water in the ratio 8:5

Final step: Mix Container A and B, find total quantity of milk.

Total parts = 8 + 7 = 15

Milk = (8/15) × 240 = 128 L

Water = 240 - 128 = 112 L

Milk removed = (8/15) × 30 = 16 L

Water removed = (7/15) × 30 = 14 L

New Milk = 128 - 16 = 112 L
New Water = 112 - 14 + 30 (water added) = 128 L

Second operation (60 L taken out, from new mix of 240 L)
New ratio of milk : water = 112:128
Total = 240 L

Milk fraction = 112/240 = 14/30
Water fraction = 128/240 = 16/30

From 60 L removal:
Milk removed = (14/30) × 60 = 28 L
Water removed = (16/30) × 60 = 32 L

Final milk in A = 112 - 28 = 84 L
Final water in A = 128 - 32 + 60 = 156 L

So final content in A = 84 L milk + 156 L water = 240

Initial milk in A = 128 L

After 30 L removal: Milk = 128 × (1 - 30/240) = 128 × (7/8) = 112 L

After 60 L removal: Milk = 112 × (1 - 60/240) = 112 × (3/4) = 84 L

Milk in B = 260 × (8/13) = 160 L

Total milk = 84 + 160 = 244 L

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