Chart 1 shows the centre-wise breakup of 8000 students who appeared for an exam at centres A to F. Chart 2 shows the breakup of the 4800 students who passed. What percentage of students who appeared at the center C passed?

Correct option is D

Given:
Chart 1: Shows number of students who appeared = 8000
Chart 2: Shows number of students who passed = 4800
We need to find: What percentage of students who appeared at center C passed?

Solution:

$$\text{Percentage appeared at center C} = 12\%\\ \Rightarrow \text{Appeared at C} = \frac{12}{100} \times 8000 = 960 \\\text{Percentage passed at center C} = 20\% \\\Rightarrow \text{Passed from C} = \frac{20}{100} \times 4800 = 960 \\\textbf{Required: Percentage of students who appeared at C and passed} \\= \frac{\text{Passed from C}}{\text{Appeared at C}} \times 100 \\\ \\= \frac{960}{960} \times 100 = 100\%$$

​Final Answer: 100%