Correct option is A
Solution:
Distinct numbers from all the statements are 3, 9, 5, 7, 1, 8, 4
Statement A: Two of the digits are present in the number 395, but they are not placed correctly.
So, the 2 digits can be 3,9 or 9,5 or 3,5
From Statement B & Statement C
The common numbers are 1 & 8. So this cannot be a possibility.
So, 1, 8, 4 is not a possible number
Since, in the 718, the digits are placed correctly. So 7 will be in hundred places.
Left with 3, 9, 5, 7
From Statements A & D we can conclude 3 & 5 are common but as said in Statement A that the number is not placed correctly.
So, 5 cannot be the number.
Now we are left with 3, 9, 7
So, the Number is 739.
Another Method:
Test each option one by one using all clues
Option (a) 739
A. Two digits are in 395 but not placed correctly.
· 395 → digits = 3, 9, 5
· 739 → digits = 7, 3, 9
· Common digits = 3 and 9 ✔
· Their positions in 739 (2nd and 3rd) ≠ positions in 395 (1st and 3rd) →
Correct per clue A
B. One digit is in 718 and placed correctly
· 718 → digits = 7, 1, 8
· 739 → 7 (1st position), matches 718's 1st digit ✔
· Only one such digit →
Correct per clue B
C. None of the digits is in 148
· 148 → digits = 1, 4, 8
· 739 → 7, 3, 9 → No match ✔
·
Correct per clue C
D. One digit is in 835 and is placed correctly
· 835 → digits = 8, 3, 5
· 739 → has digit 3 in 2nd position, and 835 has 3 in 2nd position ✔
· Only one such digit →
Correct per clue D
All clues satisfied
Conclusion:
Correct option is (a) 739
