Azim borrowed a certain sum which amounted to Rs.19,800 in 36months at 12.5% per annum simple interest. What is the borrowed sum?

Correct option is A

​​Given: 

Rate (R) = 12.5%,

Amount(A)  = Rs. 19,800,

Time(T) = 36 month= 3 years

Formula Used: 

$$S.I.=\frac{{P}\times{R}\times{T}}{100}$$ 

Amount = P + SI 

Solution:  

Applying the solution;

​$$19800 = P + \frac{P \times 12.5 \times 3}{100} \\ \ \\ 19800 = \frac{100 P+ 37.5P}{100} \\ \ \\ \frac{137.5P}{100} = 19800 \\ \ \\ P = \frac{19800 \times 100}{137.5} \\ \ \\ P = ₹14400$$​​

Thus, Principle is ₹14400

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