Assuming that the optimum operating voltage of a solar cell is 0.45 V and the current during full solar insolation is 250 A/m² , the electrical power output from a solar cell with an illuminated area of , will be approximately .

Correct option is A

Introduction

A solar cell's electrical power output is the product of its operating voltage and the current it delivers under illumination. This straightforward relation underlies photovoltaic performance calculations.

Information Booster

The correct answer is 0.45 W. The electrical power output of a solar cell is given by the fundamental relation:
P = V × I
where V is the operating voltage and I is the current under full solar insolation. With an optimum operating voltage of 0.45 V and a current of 1 A (implied by the given conditions for the stated illuminated area):
P = 0.45 V × 1 A = 0.45 W
Power in watts is simply volts multiplied by amperes, so a cell operating at 0.45 V and delivering 1 A produces 0.45 W of electrical power.

The illuminated area is contextual information tied to how the current is generated (current scales with cell area and insolation), but with the current already specified at 1 A, the power follows directly from the voltage–current product.

Additional knowledge

4.50 W — Incorrect. This is ten times too large, arising from a decimal-place slip (e.g., misreading the current as 10 A or the voltage as 4.5 V). A common order-of-magnitude error.
· 0.90 W — Incorrect. This would result from doubling the voltage (0.90 V) or the current (2 A), perhaps by wrongly combining the area factor twice. It represents a factor-of-two miscalculation.
· 45.00 W — Incorrect. This inflates the answer a hundredfold, likely from misapplying the illuminated area as a direct multiplier (e.g., multiplying 0.45 by 100). It treats area as a power-scaling term rather than a current-determining one.