An item marked for Rs. 39,250 is sold at Rs. 32,499 after allowing two successive discounts of x% and 10%. Find the value of x.

Correct option is D

Given:

Marked Price (MP) = ₹39,250

Selling Price (SP) = ₹32,499

Two successive discounts: x% and 10%

Formula Used:

Successive discount formula

SP = MP $$\times \left(1 - \frac{D_1}{100}\right) \times\left(1 - \frac{D_2}{100}\right)$$​​

​Solution: 

By Formula; 

​$$32,499 = 39,250 \times \left(1 - \frac{x}{100}\right) \times \left(1 - \frac{10}{100}\right) \\ \ \\32,499 = 39,250 \times \left(1 - \frac{x}{100}\right) \times \frac{9}{10} \\ \ \\32,499 = 35,325 \times \left(1 - \frac{x}{100}\right) \\ \ \\1 - \frac{x}{100} = \frac{32,499}{35,325} \\ \ \\1 - \frac{x}{100} = \frac{23}{25}\\ \ \\- \frac{x}{100} = \frac{23}{25} - 1 \\ \ \\ -\frac{x}{100} = -\frac{2}{25} \\ \ \\x = \frac{2}{25} \times 100 = 8 \%$$​​