An amount of ₹840 is divided among three persons in the ratio of 16 : 6 : 18. The difference between the largest and the smallest shares (in ₹) in the distribution is:

Correct option is C

Given:

Total amount = ₹840

Ratio = 16 : 6 : 18

Concept Used:

Share of each person = $$\frac{\text{Ratio part}}{\text{Sum of ratio parts}} \times \text{Total amount}$$​​

Solution: ​

Sum of ratio parts = 16 + 6 + 18 = 40

Shares:

Largest share = $$\frac{18}{40} \times 840$$​ = 378

Smallest share = $$\frac{6}{40} \times 840$$​= 126

Difference = 378 - 126 = 252