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    An aircraft is approaching the airport from a line of sight distance of 10 km to the landing point and is currently at a height of 5 km. What is the a
    Question

    An aircraft is approaching the airport from a line of sight distance of 10 km to the landing point and is currently at a height of 5 km. What is the angle of elevation?

    A.

    15°

    B.

    30°

    C.

    45°

    D.

    60°

    Correct option is B

    Given:
    Line of sight distance (hypotenuse) = 10 km
    Vertical height of the aircraft = 5 km
    Required: Angle of elevation from the landing point (horizontal) to the aircraft

    Formula Used:
    To find the angle of elevation , we use the sine function:

    sinθ=OppositeHypotenuse=510\sin \theta = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{5}{10}


    Solution:

    sinθ=510=0.5 =>θ=sin1(0.5)=30\sin \theta = \frac{5}{10} = 0.5 \\\ \\\Rightarrow \theta = \sin^{-1}(0.5) = 30^\circ

    ​Final Answer: (B) 30°

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