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An aircraft is approaching the airport from a line of sight distance of 10 km to the landing point and is currently at a height of 5 km. What is the a
Question

An aircraft is approaching the airport from a line of sight distance of 10 km to the landing point and is currently at a height of 5 km. What is the angle of elevation?

A.

15°

B.

30°

C.

45°

D.

60°

Correct option is B

Given:
Line of sight distance (hypotenuse) = 10 km
Vertical height of the aircraft = 5 km
Required: Angle of elevation from the landing point (horizontal) to the aircraft

Formula Used:
To find the angle of elevation , we use the sine function:

sinθ=OppositeHypotenuse=510\sin \theta = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{5}{10}


Solution:

sinθ=510=0.5 =>θ=sin1(0.5)=30\sin \theta = \frac{5}{10} = 0.5 \\\ \\\Rightarrow \theta = \sin^{-1}(0.5) = 30^\circ

​Final Answer: (B) 30°

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