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    Aman goes to his office by car at the speed of 80 km/hr and reaches 10 minutes earlier. If he goes at the speed 30 km/hr, then he reaches 10 minutes l
    Question

    Aman goes to his office by car at the speed of 80 km/hr and reaches 10 minutes earlier. If he goes at the speed 30 km/hr, then he reaches 10 minutes late. What will be the speed of the car to reach on time?

    A.

    480/11 km/hr

    B.

    240/6 km/hr

    C.

    450/7 km/hr

    D.

    480/13 km/hr

    Correct option is A

    Given:
    Speed when Aman reaches 10 minutes earlier: 80 km/hr
    Speed when Aman reaches 10 minutes late: 30 km/hr
    Time difference between early and late arrival: 20 minutes (10 minutes early + 10 minutes late)
    Formula Used:
    Speed = DistanceTime\frac{Distance}{Time}​​
    For reaching earlier and late from original time:
    Distance = Increased speed×Decreased speedDifference between speeds× difference between early and late arrival 60\frac{\text{Increased speed} \times\text{Decreased speed}}{\text{Difference between speeds}}\times \frac{\text{ difference between early and late arrival }}{60}​​
    Solution:
    Distance = 80×3050×2060\frac{80 \times 30}{50}\times \frac{20}{60}​ = 16 km
    Now, For original time;
    1680+1060=15+16=1130 \frac{16}{80} + \frac{10}{60} = \frac{1}{5}+ \frac{1}{6} = \frac{11}{30}​ hours
    So, Original Speed :
    161130=16×3011=48011\frac{16}{\frac{11}{30}} = \frac{16 \times 30}{11} = \bf{ \frac{480}{11}}​ km/h

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