A wire in the form of a circle of radius 56 m is cut and again bent in the form of a square. What is the measure of the diagonal of the square?

Correct option is D

Given:
Radius of circle = 56 m
Concept Used:
Circumference of the circle = Perimeter of the square
Formula Used:
Circumference = 2πr
Perimeter of square = 4 × side
Diagonal of square = $$\sqrt {2}$$​ × side 
Solution:
Circumference = 2πr = 2 × $$\frac{22}7$$​ × 56 = 352 m
Perimeter of square = 4 × side => 4s = 352 => s = 88 m
Diagonal of square = $$\sqrt{2} \times \text{side} = \sqrt{2} \times 88 = 88\sqrt{2} \, \text{m}$$