A vessel contains 79.99 liters mixture of milk and water in which milk is 50% more than water. 20.03 liters of mixture is taken out and 59.99 liters mixture of milk and water mixed in the remaining mixture into the vessel. If in the resultant mixture the milk becomes two times of the water, then find approximate quantity (in liters) of water added.

Correct option is C

Approx. value asked
Initial quantity of milk in vessel = 80 ×3/5=48 liters
Initial quantity of water in vessel = 80 – 48 = 32 liters
Let quantity of milk in the mixture mixed later = x liters
So, quantity of water in the mixture mixed later = (60 – x)
ATQ,

36 + x = 168 – 2x
x = 44
Quantity of water = 60-x = 60-44 = 16