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    A tangent is drawn from a point M to a circle, which meets the circle at T such that MT = 12 cm. a secant MAB intersects the circle at points A and B.
    Question

    A tangent is drawn from a point M to a circle, which meets the circle at T such that MT = 12 cm. a secant MAB intersects the circle at points A and B. If MA = 8 cm, what is the length (in cm) of the chord AB ?

    A.

    16

    B.

    10

    C.

    12

    D.

    9

    Correct option is B

    Given:
    Length of the tangent MT = 12 cm
    Length MA = 8 cm
    Concept Used:
    According to the tangent-secant theorem (or power of a point theorem), if a tangent and a secant are drawn from an external point to a circle, the square of the length of the tangent is equal to the product of the external part of the secant and the entire length of the secant.
    Formula Used:
    MT2=MA×MBMT^2 = MA \times MB​​
    Solution: 

    MT2=MA×MBMT2=MA×(8+AB)122=8(8+AB)18=8+AB AB=10 cmMT^2 = MA \times MB \\ MT^2 = MA \times (8+AB) \\12^2 = 8 (8+AB)\\ 18 = 8 + AB \\ \implies \bf AB = 10 \,cm​​

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