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A sum of Rs.P was borrowed and paid back in two equal yearly instalments, each of Rs.35,280. If the rate of interest was 5% per annum and interest is
Question

A sum of Rs.P was borrowed and paid back in two equal yearly instalments, each of Rs.35,280. If the rate of interest was 5% per annum and interest is compounding annually, then the value of P is ________.

A.

Rs.64,400

B.

Rs.65,600

C.

Rs.65,400

D.

Rs.64,800

Correct option is B

Given:
Principal = P (to be found)
Rate of Interest = 5% per annum (compounded annually)
Two equal yearly instalments = Rs. 35,280 each
Formula Used:
Present Value=A(1+r)1+A(1+r)2\text{Present Value} = \frac{A}{(1+r)^1} + \frac{A}{(1+r)^2}​​
Solution:
P=35,280(1+5100)+35,280(1+5100)2=>P=35,280(1+120)+35,280(1+120)2=>P=35,280(21/20)+35,280(21/20)2=>P=35,280×2021+35,280×400441=>P=35,280×2021[1+2021]=>P=35,280×2021×4121=>P=65,600P = \frac{35,280}{(1 + \tfrac{5}{100})} + \frac{35,280}{(1 + \tfrac{5}{100})^2} \\[6pt]\Rightarrow P = \frac{35,280}{(1 + \tfrac{1}{20})} + \frac{35,280}{(1 + \tfrac{1}{20})^2} \\[6pt]\Rightarrow P = \frac{35,280}{(21/20)} + \frac{35,280}{(21/20)^2} \\[6pt]\Rightarrow P = 35,280 \times \frac{20}{21} + 35,280 \times \frac{400}{441} \\[6pt]\Rightarrow P = 35,280 \times \frac{20}{21} \bigl[1 + \tfrac{20}{21}\bigr] \\[6pt]\Rightarrow P = 35,280 \times \frac{20}{21} \times \frac{41}{21} \\[6pt]\Rightarrow P = 65,600​​

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