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    A sum of ₹32,760 was taken as a loan. This is to be paid in three equal annual instalments. If the rate of interest is 20% compounded annually, then t
    Question

    A sum of ₹32,760 was taken as a loan. This is to be paid in three equal annual instalments. If the rate of interest is 20% compounded annually, then the value of each instalment is:

    A.

    ₹11000

    B.

    ₹10000

    C.

    ₹15552

    D.

    ₹16552​

    Correct option is C

    Given:

    Amount taken as loan = ₹32,760

    Instalment =3

    Rate of interest = 20%

    Formula Used:

    In case of compound interest

    Borrowed money =(x(1+r100)+x(1+r100)2+x(1+r100)3.) \left(\frac{x}{\left(1+\frac{r}{100}\right)}+\frac{x}{\left(1+\frac{r}{100}\right)^{2}}+\frac{x}{\left(1+\frac{r}{100}\right)^{3}} .…\right)​​

    Solution:

    Let the instalment be x

    32760=(x(1+20100)+x(1+20100)2+x(1+20100)3)32760 =\left(\frac{x}{\left(1+\frac{20}{100}\right)}+\frac{x}{\left(1+\frac{20}{100}\right)^{2}}+\frac{x}{\left(1+\frac{20}{100}\right)^{3}}\right)​​

    32760=(x(120100)+x(120100)2+x(120100)3)32760 =\left(\frac{x}{\left(\frac{120}{100}\right)}+\frac{x}{\left(\frac{120}{100}\right)^{2}}+\frac{x}{\left(\frac{120}{100}\right)^{3}}\right) ​​

    32760=(5x6+25x36+125x216)32760 =\left(\frac{5x}{6}+\frac{25x}{36}+\frac{125x}{216}\right)​​

    32760=(180x+150x+125x216)32760 =\left(\frac{180x+150x+125x}{216}\right)​​

    32760=(455x216)32760 =\left(\frac{455x}{216}\right)​​

    x=15,552x= ₹15,552​​

    Alternative Method:

    20%=20100=1520\% = \frac{20}{100} =\frac{1}{5}​​

    5              6 × \times ​36

    25          36  × \times​ 6

    125      216

    180        216  

    150        216  

    125        216

    Total

    455        216

    455 is equivalent to principle and 216 is the instalment 

    Now  455 = 32760

    216=32760455×216=15,552216 = \frac{32760}{455} \times 216 = ₹15,552​​

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