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Rashid borrowed a sum of ₹30,240 at 10% p.a., interest compounded annually. If the amount is to be paid back in two equal annual instalments, then the
Question

Rashid borrowed a sum of ₹30,240 at 10% p.a., interest compounded annually. If the amount is to be paid back in two equal annual instalments, then the interest paid by him is:

A.

₹4,590

B.

₹4,518

C.

₹4,600

D.

₹4,608

Correct option is D

Given:

Principal (P) = ₹30,240

Rate (R) = 10% p.a.

Time = 2 years

Repayment in 2 equal annual instalments (compounded annually)

Formula Used:

P=A(1+r)1+A(1+r)2P = \frac{A}{(1 + r)^1} + \frac{A}{(1 + r)^2}​​

Where:

P = Present value (loan amount)

A = Annual instalment

r = Rate (as a decimal)

Solution:
Given:

30240=A1.10+A(1.10)2=A1.10+A1.2130240 = \frac{A}{1.10} + \frac{A}{(1.10)^2} = \frac{A}{1.10} + \frac{A}{1.21}​​

30240=A(100110+100121)=A(1011+100121) 30240=A(110+100121) 30240=A×210121 A=30240×121210=1742430240 = A \left( \frac{100}{110}+ \frac{100}{121} \right) = A \left( \frac{10}{11}+ \frac{100}{121} \right) \\ \ \\30240= A \left( \frac{110+100}{121} \right)\\ \ \\30240=A \times \frac{210}{121}\\ \ \\A = \frac{30240 \times 121}{210} = 17424

Total repayment = 2 × 17,424 = ₹34,848

Interest = Total repayment – Principal = ₹34,848 – ₹30,240 = ₹4,608

Alternate Method:

10% = 110\frac{1}{10} 

A = 30240210×242\frac{30240 }{210}\times 242 = ₹34,848

Interest = ₹34,848 – ₹30,240 = ₹4,608​

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