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    A sum of money is distributed among four persons A,B,C and D in the ratio 4:7:9:3. If C gets Rs. 800 more than B, then find the amount that D gets.
    Question

    A sum of money is distributed among four persons A,B,C and D in the ratio 4:7:9:3. If C gets Rs. 800 more than B, then find the amount that D gets.

    A.

    Rs. 1,000

    B.

    Rs. 1,500

    C.

    Rs. 1,400

    D.

    Rs. 1,200

    Correct option is D

    Given:

    The ratio of the amounts received by A, B, C, and D is 4:7:9:3.

    C gets Rs. 800 more than B.

    Solution:

    Amount received by A = 4x, Amount received by B = 7x, Amount received by C = 9x, Amount received by D = 3x

    C gets Rs. 800 more than B.

    9x = 7x + 800

    9x −7x= 800

    2x = 800

    x = 400

    Amount received by D = 3x 

    = 3 ×\times 400

    = 1200

    So, the amount that D gets is Rs. 1200.

    Thus, correct option is (d)

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