A square park is surrounded by a path of uniform width 1.5 m all around it. The area of the path is 225 m². Find the perimeter of the park.

Correct option is C

Solution:

Let the side of the square park be s meters. Since the path is 1.5 meters wide on all sides, the total side length including the path is s + 3 meters.

The area of the path is given as 225 m². The area of the larger square (park + path) is:
​$$(s + 3)^2$$​​

The area of the park alone is ( $$s^2$$​ ).
Thus, the area of the path is:
​$$(s + 3)^2 - s^2 = 225$$​​

​$$s^2 + 6s + 9 - s^2 = 225$$​​

6s + 9 = 225

6s = 216

s = 36

The perimeter of the square park is:
​$$4 \times s = 4 \times 36 = 144$$​​
The perimeter of the park is 144 meters.