A shopkeeper uses a weight of 950 gm instead of 1 kg and sells the articles at the marked price. which is 15% above the cost price. What is his profit percentage?

Correct option is C

Given:

A shopkeeper uses a weight of 950 grams instead of 1 kilogram.

The shopkeeper sells the articles at the marked price, which is 15% above the cost price.

Formula Used:

​$$Cost Price of a Quantity=Cost Price of 1 kg× \frac{Given Weight (gm)}{1000gm}​$$

​​Profit Percentage = $$(\frac{profit}{Cost\ Price}) \times100$$

Solution:

The cost price of 950 g is

Actual Cost Price for 950 g = Cost price of 1 kg $$\times$$ $$\frac{950}{1000}$$ = $$x \times 0.95$$ = $$0.95x$$

​​The profit for selling 950 g is

Profit = Selling Price − Cost Price = 1.15x − 0.95x = 0.2x

Profit Percentage = $$(\frac{0.2x}{0.95x}) \times100$$

​​Profit Percentage = $$(\frac{20}{95}) \times100$$

​​Profit Percentage = $$(\frac{4}{19}) \times100$$ 

Profit Percentage = $$21\frac{1}{19}$$ %

​

​​

Cost price of 950 g=Cost price of 1 kg×9501000=x×0.95=0.95x\text{Cost price of 950 g} = \text{Cost price of 1 kg} \times \frac{950}{1000} = x \times 0.95 = 0.95x