A shopkeeper marks up the price of the oil by 40% and uses a faulty machine which measures 15% less. If the shopkeeper gives a discount of 32%, the profit/loss percentage is:

Correct option is D

Given:
Marks up the price of the oil = 40%
Less measures = 15%
Discount =32%
Solution:
Let the price of the oil be Rs. 100
MP of oil = 100 ×$$\frac{140}{100}$$​= 140
Shopkeeper uses a faulty machine which measures 15% less.
Then the actual CP = 100 ×$$\frac{85}{100}$$​=85
Discount will be on MP = 140 ×$$\frac{68}{100}$$​=95.2
As per the question,
Profit% = $$\frac{95.2-85}{85}$$​ ×100
= $$\frac{10.2}{85}$$​ ×100= 12%
Alternate Method: Ratio method
CP : SP
100 : 140
(100-15) = 85 : 100
100 : (100-32) = 68
_________________________________________________________
100 × 85 × 100 : 140 ×100 × 68
100 × 85 : 140 ×68
25 : 28
Profit% = $$\frac{28 - 25}{25}$$​ ×100=12%