A shopkeeper buys three varieties of pulses at Rs 132, Rs 160 and Rs y per kg respectively and mixes them in the ratio 9 : 2 : 1. The marked price per kg of the blended pulses is fixed at Rs 238, the shopkeeper gives a discount equal to $$\frac{1}{6}$$​ of the marked price and still earns a profit of 40%. What is the value of y?

Correct option is A

Given:
The shopkeeper buys three varieties of pulses at ₹132, ₹160, and ₹y per kg respectively.
The pulses are mixed in the ratio 9:2:1.
The marked price per kg of the blended pulses is ₹238.
The shopkeeper gives a discount of $$\frac{1}{6}$$​ of the marked price and still earns a profit of 40%.

Formula Used:

$$\text{Cost Price (per kg)} = \frac{(P_1 \times Q_1 + P_2 \times Q_2 + P_3 \times Q_3)}{Q_1 + Q_2 + Q_3}$$  

$$\text{Selling Price} = \left(1 - \frac{\text{Discount}}{100}\right) \times \text{Marked Price}$$​

Solution:

Cost Price =  $$\frac{132\times 9 + 160 \times 2 + y \times 1}{12}$$ = $$\frac{1188 + 320 + y }{12}$$ = $$\frac{1508 + y }{12}$$  

Since, Marked Price = 238

Selling Price = $$\frac{5}{6}$$ $$\times 238$$

Since, Profit = 40% = $$+\frac{2}{5}$$  = $$\frac{7}{5}$$

$$\frac{5}{6} \times 238 = \frac{7}{5} \times \frac{1508 + y}{12}$$ 

$$5 \times 238 = \frac{7}{10} \times1508 + y$$

1700 = 1508 + y

y = 1700 - 1508

y = 192

Thus, the correct option is (a) 192