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A reduction of 7.5% in the cost price of a commodity enables a shopkeeper to purchase 15 kg more than what he previously purchased for a sum of ₹7,400
Question

A reduction of 7.5% in the cost price of a commodity enables a shopkeeper to purchase 15 kg more than what he previously purchased for a sum of ₹7,400. In order to make a profit of 32.5% on the pre-reduction cost price of the commodity, at what price (in ₹) per kg should the commodity be sold?

A.

54

B.

52

C.

51

D.

53

Correct option is D

​Given:
Total money = ₹7,400
Reduction in cost price = 7.5%
After reduction, 15 kg more can be bought with the same amount
Required profit = 32.5% on the original (pre-reduction) cost price
Formula Used:
Quantity purchased = Total moneyCost price per kg\frac{\text{Total money}} {\text{Cost price per kg}}​​

Selling price per kg = Cost price × (1+Profit %100)\left( 1+ \frac{\text{Profit \%}}{100}\right)​​
Solution:
Let original cost price = x ₹/kg
Then,
Quantity at original price =  7400x\frac{7400}{x}

Then, after 7.5% reduction, the new cost price = x7.5% of x=0.925xx - 7.5\% \text{ of } x = 0.925x​​

Quantity at reduced price = 74000.925x\frac{7400}{0.925x}

Difference in quantity = 15 kg
So:
74000.925x7400x=15\frac{7400}{0.925x} - \frac{7400}{x} = 15

7400x0.925x7400=15x\frac{7400x}{0.925x} - 7400 = 15x

=>74000.9257400=15x\Rightarrow \frac{7400}{0.925} - 7400 = 15x

74000.925=8000\frac{7400}{0.925} = 8000

=>80007400=15x\Rightarrow 8000 - 7400 = 15x​​
=> 15 x = 600

=> x = 60015\frac{600}{15} 40​
So, original cost price per kg = ₹40

Now, required selling price to make 32.5% profit:

SP =  40×(1+32.5100)=40×1.325=5340 \times \left(1 + \frac{32.5}{100}\right) = 40 \times 1.325 = ₹53

The selling price should be ₹53 per kg.

Thus, the correct option is (d) ₹53


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