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    A reduction of 7.5% in the cost price of a commodity enables a shopkeeper to purchase 15 kg more than what he previously purchased for a sum of ₹7,400
    Question

    A reduction of 7.5% in the cost price of a commodity enables a shopkeeper to purchase 15 kg more than what he previously purchased for a sum of ₹7,400. In order to make a profit of 32.5% on the pre-reduction cost price of the commodity, at what price (in ₹) per kg should the commodity be sold?

    A.

    54

    B.

    52

    C.

    51

    D.

    53

    Correct option is D

    ​Given:
    Total money = ₹7,400
    Reduction in cost price = 7.5%
    After reduction, 15 kg more can be bought with the same amount
    Required profit = 32.5% on the original (pre-reduction) cost price
    Formula Used:
    Quantity purchased = Total moneyCost price per kg\frac{\text{Total money}} {\text{Cost price per kg}}​​

    Selling price per kg = Cost price × (1+Profit %100)\left( 1+ \frac{\text{Profit \%}}{100}\right)​​
    Solution:
    Let original cost price = x ₹/kg
    Then,
    Quantity at original price =  7400x\frac{7400}{x}

    Then, after 7.5% reduction, the new cost price = x7.5% of x=0.925xx - 7.5\% \text{ of } x = 0.925x​​

    Quantity at reduced price = 74000.925x\frac{7400}{0.925x}

    Difference in quantity = 15 kg
    So:
    74000.925x7400x=15\frac{7400}{0.925x} - \frac{7400}{x} = 15

    7400x0.925x7400=15x\frac{7400x}{0.925x} - 7400 = 15x

    =>74000.9257400=15x\Rightarrow \frac{7400}{0.925} - 7400 = 15x

    74000.925=8000\frac{7400}{0.925} = 8000

    =>80007400=15x\Rightarrow 8000 - 7400 = 15x​​
    => 15 x = 600

    => x = 60015\frac{600}{15} 40​
    So, original cost price per kg = ₹40

    Now, required selling price to make 32.5% profit:

    SP =  40×(1+32.5100)=40×1.325=5340 \times \left(1 + \frac{32.5}{100}\right) = 40 \times 1.325 = ₹53

    The selling price should be ₹53 per kg.

    Thus, the correct option is (d) ₹53


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