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A rectangular sheet 31.4 cm x 10 cm is rolled across its length to make a cylinder and both ends of the cylinder are covered with additional circular
Question

A rectangular sheet 31.4 cm x 10 cm is rolled across its length to make a cylinder and both ends of the cylinder are covered with additional circular sheets. What will be the total surface area of the covered cylinder approximately?

A.

314 cm²

B.

392.5 cm²

C.

471 cm²

D.

785 cm²

Correct option is C

Given:

  • A rectangular sheet of 31.4 cm × 10 cm
  • The sheet is rolled across its length to form a cylinder
  • Both ends are covered with circular sheets
  • We are to find the total surface area of the closed cylinder

Formula Used:

Total Surface Area of a closed cylinder =
2πr² (area of top and bottom) + 2πrh (lateral surface area)

Where:

  • r = radius of the base
  • h = height of the cylinder

Solution:

Since the sheet is rolled along its length (31.4 cm), this becomes the circumference of the base of the cylinder.

So,

Step 1: Find the radius

Circumference = 2 × π × r = 31.4
Using π ≈ 3.14:

2 × 3.14 × r = 31.4
6.28 × r = 31.4
r = 31.4 ÷ 6.28 = 5 cm

Step 2: Height of cylinder = 10 cm (the width of the rectangular sheet)

Step 3: Calculate total surface area

  • Area of two circular ends = 2 × π × r² = 2 × 3.14 × 5² = 2 × 3.14 × 25 = 157 cm²
  • Lateral surface area = 2 × π × r × h = 2 × 3.14 × 5 × 10 = 314 cm²

Step 4: Add both areas

Total surface area = 157 + 314 = 471 cm²

Final Answer: (C) 471 cm²

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