A policeman starts chasing a thief when he was already 600 m ahead. If the policeman is running at a speed of 9 km/h and the thief at 8 km/h, then the thief would be caught at a distance of:

Distance between the policeman and the thief initially = 600 m

Speed of the policeman = 9 km/h

Speed of the thief = 8 km/h

Relative speed = Speed of the policeman - Speed of the thief

Time taken to catch the thief = $$\frac{\text{Initial distance}}{\text{Relative speed}}$$​​

Distance covered by the policeman to catch the thief = $$\text{Speed of the policeman} \times \text{Time taken}$$ 

Solution:   ​

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