A photograph of a bacteria enlarged 60000 times attains a length of 6 cm. The actual length of bacteria is:

Correct option is B

Given:

The photograph of the bacteria is enlarged 60,000 times.

The length of the enlarged bacteria is 6 cm.​

Solution:

Actual Length =$$\frac{6 \, \text{cm}}{60,000} = \frac1{10000}$$ cm​