Correct option is D
Given,
A man has = Rs. 320.
Coins of 1-rupee, 2-rupee and 5-rupee are equal.
Concept:
If N is divided into a : b, then
First part = N × a/(a + b)
Second part = N × b/(a + b)
Solution:
If coins of 1-rupee, 2-rupee and 5-rupee is equal,
Let the number of coins each of 1, 2 and 5 rupee be k
According to the question
k + 5k + 2k = 320
8k = 320
k = 320/8
k = 40
∴ Total number of coins = 3 × 40 = 120