Correct option is C
Given:
Cost of 3 pens and 12 notebooks = ₹195
Cost of 7 notebooks exceeds cost of 4 pens by ₹39
Solution:
Let the cost of one pen = ₹x
Let the cost of one notebook = ₹y
So,
3x + 12y = 195 …(1)
7y = 4x + 39 => 7y - 4x = 39 …(2)
From (2):
7y - 4x = 39
Multiply (1) by 4 and (2) by 3 to eliminate x:
(1) × 4 => 12x + 48y = 780
(2) × 3 => 21y - 12x = 117
Now add both:
(12x + 48y) + (−12x + 21y) = 780 + 117
=> 69y = 897
=> y = ₹13
Substitute y = 13 in (1):
3x + 12×13 = 195
3x + 156 = 195
3x = 39
x = ₹13
Now, cost of 12 pens and 6 notebooks = 12x + 6y
= 12×13 + 6×13 = 156 + 78 = ₹234