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A person borrowed some money on simple interest. After 3 years, he returned 4/3 of the money to the lender. What was the rate of interest?
Question

A person borrowed some money on simple interest. After 3 years, he returned 4/3 of the money to the lender. What was the rate of interest?

A.

1129\frac29​% p.a.

B.

1139\frac39​% p.a.

C.

1149\frac49​% p.a.

D.

11 19\frac19​% p.a.

Correct option is D

Given:
Principal amount (P) = Let the borrowed amount be P
Time (T) = 3 years
Amount returned =43P \frac{4}{3} P​​
Simple Interest (SI) = Amount returned - Principal = 43PP=P3\frac{4}{3} P - P = \frac{P}{3}​​
Formula Used:
Simple Interest (SI) = P×R×T100\frac{P \times R \times T}{100}​​
Solution:
P3=P×R×3100 13=R×3100 R=1009=11.11% \frac{P}{3} = \frac{P \times R \times 3}{100}\\\ \\\frac{1}{3} = \frac{R \times 3}{100}\\\ \\R = \frac{100}{9} = 11.11\%\\\ \\​​
Thus, the rate of interest is 11.11% = 1119\frac19​​%

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