A number is first increased by 12%, and the increased number is decreased by 8%. Findthe net increase or decrease percentage.

Correct option is C

Given:

The first percentage increase (x) = 12%

The second percentage decrease (y) = 8%

Formula Used:

Net percentage change = $$x + y + \frac{xy}{100}$$​​

Solution:

Net percentage change = $$12 + (-8) + \frac{12 \times (-8)}{100}$$​​

​$$= 12 - 8 + \frac{-96}{100}$$​​

= 12 - 8 - 0.96

= 3.04

Therefore, the net percentage increase of 3.04%