A number is divided into two parts such that one part of the number is 10 more than the other part, and the ratio of the two parts is 4: 3. Find the initial number,

Correct option is B

Given:

One part of the number is 10 more than the other part.

The ratio of the two parts is 4:3

Solution:

Let the smaller part of the number be x

Then the larger part is x +10

Given ratio (4:3):

​$$\frac{x+10}{x} = \frac{4}{3}$$

​​3 (x+10) = 4x

3x +30 = 4x

4x − 3x = 30

x = 30

Smaller part x =30

Larger part x+10 = 30+10 = 40 

sum of the two parts

30+40 =70

The initial number is 70.​