A number 37 is divided into two parts such that 5 times one part and 11 times the other is together equal to 227. Find the
value of 9 times the smaller number.

Correct option is D

Given:

A number 37 is divided into two parts.

5 times one part and 11 times the other part together equal 227.

Solution:

Let the two parts be x and 37 - x.

Let the two parts of 37 be x and 37 - x.

The condition is:

5x + 11(37 - x) = 227

5x + 407 − 11x = 227

-6x = 227 - 407

−6x = −180

x =$$\frac{-180}{-6} = 30$$​

The smaller number is 37 - x = 37 - 30 = 7.

The value of 9 times the smaller number is:

9 × 7 = 63

Thus, the value of 9 times the smaller number is 63.