A money bag contains one rupee, 5 rupee and 10 rupee coins in the ratio of 3 : 5 : 7 respectively. If the total amount in the bag is Rs. 980, then find the number of coins of Rs. 10.
Given:
Total value of coins =Rs 980
Ratio of number of Re 1, Rs 5 and Rs 10 coins are 3:5:7 respectively
Solution:
Let the number of coins of Re 1, Rs 5 and Rs 10 be 3x, 5x and 7x respectively
Then according to question
3x(1) + 5x(5) + 7x(10) = 980
3x+25x+70x =980
98x =980
x=10
Number of Rs 10 coins are = 7x =70 coins
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