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A hemispherical bowl of Internal radii of 12 cm contains a liquid. this liquid is to be filled into conical shaped small bottles of base diameter 3 cm
Question

A hemispherical bowl of Internal radii of 12 cm contains a liquid. this liquid is to be filled into conical shaped small bottles of base diameter 3 cm and height 4 cm. How many same type of bottles will be needed to empty the bowl?

A.

520

B.

384

C.

438

D.

400

Correct option is B

Given:
Internal radius of hemispherical bowl (r) = 12 cm
Base diameter of conical bottle = 3 cm
Base radius of conical bottle (R) = 1.5 cm
Height of conical bottle (h) = 4 cm
Formula used:
 Volume of hemispherical bowl =23πr3 Volume of one conical bottle =13πR2h\begin{aligned}& \text { Volume of hemispherical bowl }=\frac{2}{3} \pi r^3 \\& \text { Volume of one conical bottle }=\frac{1}{3} \pi R^2 h\end{aligned} 
Solution:
 Volume of hemispherical bowl =23π(12)3=> Volume of hemispherical bowl =23π×1728=> Volume of hemispherical bowl =1152π cm3 Volume of one conical bottle =13π(1.5)2×4\begin{aligned}& \text { Volume of hemispherical bowl }=\frac{2}{3} \pi(12)^3 \\& \Rightarrow \text { Volume of hemispherical bowl }=\frac{2}{3} \pi \times 1728 \\& \Rightarrow \text { Volume of hemispherical bowl }=1152 \pi \mathrm{~cm}^3 \\& \text { Volume of one conical bottle }=\frac{1}{3} \pi(1.5)^2 \times 4\end{aligned} 
=> Volume of one conical bottle =13π×2.25×4=> Volume of one conical bottle =3π cm3 Number of bottles needed =1152π3π=> Number of bottles needed =384\begin{aligned}& \Rightarrow \text { Volume of one conical bottle }=\frac{1}{3} \pi \times 2.25 \times 4 \\& \Rightarrow \text { Volume of one conical bottle }=3 \pi \mathrm{~cm}^3 \\& \text { Number of bottles needed }=\frac{1152 \pi}{3 \pi} \\& \Rightarrow \text { Number of bottles needed }=384\end{aligned} 
Thus, the correct answer is (B).

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