A hemispherical bowl is made of steel whose thickness is 2 cm . The inside radius of the bowl is 3 cm . Find the volume (in $$cm^3$$​ ) of the steel used in making the bowl. (Rounded off to 2 decimal places) (Take π=$$\frac{22}{7}$$​ )

Correct option is D

Given:

Thickness of steel =2cm

Inside radius of bowl =3cm

Formula Used:

Volume of hemisphere =$$\frac{2}{3}\pi (r_1)^3 - (r_2)^3$$​​

Where$$r_1,r_2$$​are the outer and inner radius of hemisphere respectively

Solution:

Outer radius of hemispherical bowl = 3+2 = 5cm

Volume of steel used =$$\frac{2}{3}\pi (5)^3 - (3)^3$$​​

​$$= \frac{2}{3}\times \frac{22}{7} \times (125 -27)$$​​

​$$=205.33cm^3$$​​