A cylindrical rod has an outer curved surface area of 8800 cm². If the length of the rod is 87 cm, then the outer radius (in cm) of the rod, correct to two places of decimal, is:
Take π = 22/7

Correct option is D

Given:

Curved Surface Area (CSA) = 8800 cm²

Length (height) of cylinder, h = 87 cm=

Formula Used:

Curved Surface Area (CSA) = 2πrh

Solution: 

Applying the formula;

8800 = 2πr(87)

r = $$\frac{8800}{2 × \frac{22}{7} × 87}$$​​

=$$\frac{8800 × 7}{2 × 22 × 87}$$​​

= $$\frac{61600}{3828} ≈ 16.09 \text{ cm}$$​​

Thus, The outer radius of the rod is 16.09 cm