A cylindrical rod has an outer curved surface area of 6200 cm². If the length of the rod is 32 cm, then the outer radius (in cm) of the rod, correct to two places of decimal, is: Take $$π = \frac{22}{7}​$$​​

Correct option is A

​Given:

Outer curved surface area A = 6200 \, \text{cm}^2

Length l = 32 cm

π =$$\frac{22}{7}$$​​

Formula Used:

The formula for the curved surface area (CSA) of a cylinder is:

A = 2πrl

Where:

A = curved surface area

r = radius

l = length of the cylinder

Solution:

Substitute the known values into the formula:

​$$6200 = 2 \times \frac{22}{7} \times r \times 32 \\ \ \\6200 = \frac{44}{7} \times r \times 32 \\ \ \\6200 \times 7 = 44 \times r \times 32 \\ \ \\r = \frac{43400}{1408} = 30.82 \, \text{cm}$$​​

Thus, the outer radius of the rod is 30.82 cm.