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A cylindrical rod has an curved surface area of 4,900 cm². If the length of the rod is 97 cm, then the radius (in cm) of the rod, correct to two
Question

A cylindrical rod has an curved surface area of 4,900 cm². If the length of the rod is 97 cm, then the radius (in cm) of the rod, correct to two places of decimal, is:
Take π=227\pi = \frac{22}{7}

A.

6.97

B.

8.55

C.

7.95

D.

8.04

Correct option is D

Given:

Curved Surface Area (CSA) = 4,900 cm²

Height (length) h = 97 cm

Formula Used:

Curved Surface Area of a cylinder = 2πrh

Solution: 

CSA of cylinder = 2×227×r×972 \times \frac{22}{7} \times r \times 97  

4900 = 2×227×r×972 \times \frac{22}{7} \times r \times 97

r =49002×227×97 \frac{4900}{2 \times \frac{22}{7} \times 97}​   =3430042688.039= \frac{34300}{4268} \approx 8.039​​

r = 8.04 cm

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