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    A cuboid having the surface area of 3 adjacent faces as a, b, c has the volume:
    Question

    A cuboid having the surface area of 3 adjacent faces as a, b, c has the volume:

    A.

    a3b3c3

    B.

    (abc)13(abc)^{\frac{1}{3}}​​

    C.

    abc

    D.

    (abc)(1/2)(abc)^{(1/2)}​​

    Correct option is D

    Given:
    The Areas of 3 adjacent faces of cuboid = a, b & c
    Formula used:
    The volume of cuboid = Length × Breadth × Height
    Solution:
    The area of one face is lB =a
    The area of the second face is BH=b
    The area of the third face is lh=c
    The volume of the cuboid is V=L⋅B⋅H By rearranging these three area equations, we get
    So, a = L × B; b = B × H; c = H × L
    abc = (L × B) × (B × H) × (H × L)
    abc = L2 × B2 × H2
    L × B × H = √abc
    The volume of cuboid = √abc
    (abc)(1/2)(abc)^{(1/2)}​​

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