A cubical block of side 10 cm and with a mass of 600 g floats in water. How much of the cube is submerged?

Correct option is A

​$$\text{Step 1: Find the volume of the cube}\\\text{Side of cube} = 10\ \text{cm}\\[6pt]V = a^3 = 10^3 = 1000\ \text{cm}^3\\[10pt]\text{Step 2: Calculate the density of the cube}\\\text{Mass} = 600\ \text{g}\\[6pt]\rho_{\text{cube}} = \frac{\text{Mass}}{\text{Volume}}= \frac{600}{1000}= 0.6\ \text{g/cm}^3\\[10pt]\text{Density of water:}\\[6pt]\rho_{\text{water}} = 1\ \text{g/cm}^3\\[10pt]\text{Step 3: Determine the fraction submerged}\\\text{For a floating object:}\\[6pt]\frac{\text{Volume submerged}}{\text{Total volume}}=\frac{\rho_{\text{cube}}}{\rho_{\text{water}}}=\frac{0.6}{1}=0.6\\[10pt]\text{Percentage submerged}=0.6 \times 100=60\%$$​​