If current =1.414 A and resistance = 50Ω, then find power

Correct option is C

​$$\text{Given, current } (I) = 1.414 \text{ A} = \sqrt{2} \text{ A}, \\\text{Resistance } (R) = 50\Omega \\P = I^2 R = (1.414)^2 \times 50 \\= (\sqrt{2})^2 \times 50 = 2 \times 50 = 100 \text{ watt} \\= 100 \text{ watt}$$​​