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    A coil of inductance 10 H and resistance 40 ohm is connected in series with a capacitance and supplied by a source of variable frequency. If the maxim
    Question

    A coil of inductance 10 H and resistance 40 ohm is connected in series with a capacitance and supplied by a source of variable frequency. If the maximum current is found at frequency 1000 rad/sec, then Q-factor of the circuit will be _________.

    A.

    25

    B.

    200

    C.

    100

    D.

    250

    Correct option is D

    Given: Inductance L=10 H Resistance R=40 Ω Angular frequency ω=1000 rad/secThe Quality Factor (QF) is given by the formula:QF=ωLRSubstitute the given values into the formula:QF=1000×1040QF=1000040=250So, the quality factor QF of the circuit is 250.\text{Given:} \\[4pt]\bullet \; \text{Inductance } L = 10\,\text{H} \\[4pt]\bullet \; \text{Resistance } R = 40\,\Omega \\[4pt]\bullet \; \text{Angular frequency } \omega = 1000\,\text{rad/sec} \\[8pt]\text{The Quality Factor (QF) is given by the formula:} \\[4pt]QF = \frac{\omega L}{R} \\[8pt]\text{Substitute the given values into the formula:} \\[4pt]QF = \frac{1000 \times 10}{40} \\[4pt]QF = \frac{10000}{40} = 250 \\[8pt]\text{So, the quality factor } QF \text{ of the circuit is } 250.​​

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