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A closed wooden box measures externally 10 cm long, 8 cm broad and 6 cm high. If the thickness of the wood is 0.5 cm, then the volume of wood required
Question

A closed wooden box measures externally 10 cm long, 8 cm broad and 6 cm high. If the thickness of the wood is 0.5 cm, then the volume of wood required is:

A.

165 cm³

B.

300 cm³

C.

230 cm³

D.

150 cm³

Correct option is A

Given:
Length (L) = 10 cm
Breadth (B) = 8 cm
Height (H) = 6 cm
Thickness of the wood (T) = 0.5 cm 
Formula Used: 
External volume of the box:
Vext=Length×Breadth×HeightV_{\text{ext}} = \text{Length} \times \text{Breadth} \times \text{Height}​​
Internal dimensions:
Internal length = External length - 2 × Thickness
Internal breadth = External breadth - 2 × Thickness
Internal height = External height - 2 × Thickness
Internal volume of the box:
Vint=Internal length×Internal breadth×Internal heightV_{\text{int}} = \text{Internal length} \times \text{Internal breadth} \times \text{Internal height}​​
Volume of wood required:
Vwood=VextVintV_{\text{wood}} = V_{\text{ext}} - V_{\text{int}}​​
Solution:
The internal dimensions of the box will be reduced by the thickness of the wood on each side:
Internal Length = L - 2T = 10 - 2(0.5) = 9 cm
Internal Breadth = B - 2T = 8 - 2(0.5) = 7 cm
Internal Height = H - 2T = 6 - 2(0.5) = 5 cm
External Volume = L ×\times​ B ×\times​ H = 10 ×\times​8 ×\times​ 6 = 480 cubic cm
Internal Volume = Internal Length ×\times​ Internal Breadth ×\times​ Internal Height = 9 ×\times​ 7 ×\times​ 5 = 315 cubic cm
Volume of Wood = External Volume -  Internal Volume = 480 - 315 = 165 cubic cm

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